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Atlas · Foundations capacity-and-placement

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Capacity AND Placement

A capacity limit states how much a container can hold; a placement assigns whole items to containers while keeping each total within that limit.

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    Beginner field notes

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    • Capacity is the most one bin may hold in the stated unit. In the lesson’s capacity-10 bin, a size-4 item leaves 6 units free.
    • Each item stays whole and is placed exactly once. Splitting or silently dropping an item is not a valid way to make this model fit.
    • A load of 10 meets a capacity of 10; a load of 11 exceeds it. Check every bin’s load, not just the total across all bins.
    See a worked example

    Check a placement before asking whether it is best

    Sample only. Nothing here runs on your computer.

    Example input · do not paste
    OFFLINE Lantern Archive paper placement; no boxes, machines or files are actually changed.
    Four distinct, whole items: A size 4, B size 4, C size 6, D size 6. Each item must be assigned exactly once and cannot be split. Sizes are positive integer units of one additive resource; every bin has capacity 10. A bin is legal when its total is at most 10, so equality is allowed. Ignore shape, overhead, timing, CPU/memory combinations, affinity and every other constraint.
    Start with no bins. Give each newly opened bin the next label P1,P2,P3. Once an item is assigned, do not move or remove it. There are enough identical bins; each item fits an empty bin.
    First-fit rule: take items in the stated order. Check already opened bins in their opening order; put the item in the first whose remaining capacity is at least its size. If none fits, open a new bin and put it there.
    Use input order A4, B4, C6, D6. After each item, show the selected bin, contents, load and remaining capacity. Does every final bin satisfy the limit?
    Example output · do not paste
    A4: open P1. P1=[A], load 4, remaining 6.
    B4: P1 is the first fit. P1=[A,B], load 8, remaining 2.
    C6: P1 remaining 2 is too small; open P2. P2=[C], load 6, remaining 4. P1 remains unchanged.
    D6: P1 remaining 2 and P2 remaining 4 are too small; open P3. P3=[D], load 6, remaining 4.
    Final bins: P1=[A,B] load 8/10; P2=[C] load 6/10; P3=[D] load 6/10. All four items occur exactly once; all loads are within 10. Three bins are used.
    This is a valid placement under the given rule; the capacity check alone does not prove it uses the fewest bins.

    Track each bin independently and subtract its current load from 10 before assigning the next whole item. The three-bin result follows the supplied input order and first-fit rule. It satisfies capacity and exact-once placement; it does not establish a minimum, and no actual bin or resource is created.

    Visual

    The given first-fit order puts A and B in P1, C in P2 and D in P3. Loads 8, 6, 6 each satisfy capacity 10. This picture checks one valid placement, not a minimum-bin guarantee.

    The reviewed description and complete diagram source are available here.

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    flowchart LR
      A["A size 4"] --> P1["P1: A+B; load 8 of 10"]
      B["B size 4"] --> P1
      C["C size 6"] --> P2["P2: C; load 6 of 10"]
      D["D size 6"] --> P3["P3: D; load 6 of 10"]
      P1 --> V["All items once; each bin within capacity"]
      P2 --> V
      P3 --> V
    Sources and full explanation

    Notes sources · Beginner

    AI source review · 2026-10-17

    Reviewed explanation

    A capacity limit says how much one container can hold under a stated rule. A placement says which item goes into which container. In the fictional Lantern Archive, a paper bin holds at most 10 units of one resource. An item labeled A uses 4 units. Put A in an empty bin and its load becomes 4, leaving 6. No terminal, programming language or network lesson is needed to follow that arithmetic.

    We must first define what fits. Items are whole and indivisible here, so a 6-unit item needs 6 free units in one bin. Two separate bins with 2 and 4 free units do not give that item a usable 6-unit slot. A total of 10 meets the limit exactly; a total of 11 does not. Every item must be placed exactly once, and all sizes use the same additive unit.

    A constraint tells us which placements are allowed. An objective tells us which allowed placement we prefer. Keeping every bin within 10 is the capacity constraint. Trying to use the fewest bins is a possible objective, but passing a capacity check is not proof that the objective is best. A different legal arrangement can use a different number of bins.

    To make the paper trace unambiguous, we choose first-fit: process the listed items in order and scan existing bins in their opening order. Use the first that has enough remaining capacity, or open the next labeled bin if none does. Earlier assignments stay fixed. A and B take 8 units together; the following 6-unit items each need a new bin under that rule.

    These are mathematical bookkeeping rules, not a description of a live storage system or scheduler. Our one-dimensional model omits shape, overhead, timing and combinations such as CPU plus memory. Such extra constraints must be modeled separately if they matter. Reading the worked trace assigns no real resource, and the number of bins supplies no performance or cost guarantee.

    AI source comparison recorded 2026-10-17. Human learner validation is pending.

    Quick quiz · one question

    Follow capacity checks without moving items

    Sample scenario. Offline Lantern Archive paper procedure, distinct from an automatic optimizer. One additive resource, capacity 10, whole items A size 4, B size 4, C size 6, D size 6. Every item fits alone. Open only the next numbered container when a listed valid attempt first uses it. Refuse an overfull attempt and retain its unplaced item; retry is allowed. No split, move, removal or automatic repacking.

    Paper capacity
    Each container holds at most 10 integer units of one additive resource. Items are whole and each fits alone. No splitting, moving, removal, hidden repacking, real allocation or other constraint.
    Distinct items
    A: size 4; B: size 4; C: size 6; D: size 6
    Trial manual
    Only the listed manual targets apply. Open at most the next numbered container when needed; refuse overfull tries and retain the unplaced item for a later attempt.
    manual: attempt 1
    Try whole item A in P1.
    manual: attempt 2
    Try whole item B in P1.
    manual: attempt 3
    Try whole item C in P1.
    manual: attempt 4
    Try whole item C in P2.
    manual: attempt 5
    Try whole item D in P1.
    manual: attempt 6
    Try whole item D in P2.
    manual: attempt 7
    Try whole item D in P3.

    Follow only the seven stated placement attempts. Which containers exist at the end, and what happens to an item after an overfull attempt is refused?

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    Sources and exercise scope
    • NIST Dictionary of Algorithms and Data Structures: bin packing problem

      Defines constrained packing and the common fewest-fixed-capacity-bins objective, while distinguishing variants such as dimensions and resource measures. It does not equate this one-dimensional example with a real scheduler.

    • Mathematical Optimization book: Bin packing and cutting stock problems

      The method authors describe non-increasing-size preprocessing followed by the first open bin that fits, opening another only when needed. They explicitly distinguish a heuristic from guaranteed optimization. The chapter also illustrates an instance-specific total-capacity lower bound. Only these explanations are used; its code/solver setup is not executed.

    Original synthetic exercise. AI comparison against the reviewed lesson recorded on 2026-10-17; the references above state their scope. Human learner validation has not been run. A result here records this attempt; it does not establish mastery.

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